Thursday, 19 January 2012

Algebra Change of Subject 2(review)

Task 2
Pair work (follow-up from previous Task Algebra Change of Subject 2)

Based on the activity in task 1, students have submitted the following responses (refer Table 1).


Your task is to reflect on the solution(s) submitted by your classmates.
Identify at least 2 points for consideration for 'Change of Subject'. Example Arithmetic error (wrong associative law applied)
You may discuss with a partner in class.

Submit this as a comment.
Indicate your name as well as your partner's name.

reference:
Worksheet 5, ACE learning.


Question Posted by Teacher





Table 1: Answer Posted by Students




















20 comments:

  1. Student D:
    Error: Did not change the right hand side of the equation from + to - when he changed the left hand side from - to + and did not divide 2z by p.

    ReplyDelete
  2. Tan Yu Tao, Jonathan Tan
    Multiplication and division error
    Arithmetic error

    ReplyDelete
  3. Student D:
    He/She did not divide the 2z by the p and also did not change the addition and subtraction symbols properly.

    ReplyDelete
  4. Student A,B,L,Q,C,E,H,I,M,R = Did not inverse the operation from + to -
    Student
    Student F = Correct
    Student D = Forgot to divide P
    Student J = The subject should only be on the left

    By Sylvia and Esther

    ReplyDelete
  5. This comment has been removed by the author.

    ReplyDelete
  6. Student A,B,L,Q,C,E,H,I,M,R = Did not inverse the operation from + to -
    Student
    Student F = Correct
    Student D = Forgot to divide P
    Student J = The subject should only be on the left

    By Sylvia and Esther

    ReplyDelete
  7. Student "I" has left the "ans)" there and did not find the solution for z-2z which should be -z.

    ReplyDelete
  8. Student C:
    Did not change the right hand side of the equation from multiplication to division. So in stead of 2z/p it became 2zp.

    ReplyDelete
  9. Student N- The 2z should be a fraction with the p instead, 2z the numerator while p the denominator .

    ReplyDelete
  10. Student C did not divide the equation by p and he did not change the signs for both sides of the equation.

    ReplyDelete
  11. Student C did not make the 2z divide by p

    ReplyDelete
  12. Student N - The 2z should actually be the fraction with p.

    ReplyDelete
  13. student D did not make the 2z divided by p, but multiplied it instead

    ReplyDelete
  14. Only Student F got it correct, Student D is close but he/she did not divide p. Student J is correct except the fact that the subject is on the right side. The rest got the question wrong because they did not inverse the answer.

    ReplyDelete
  15. Student G :

    Did not change + to - when changing sides for 2z

    pz is supposed to be a + not a -

    ReplyDelete
  16. Student C:
    Arithmetic error, when he transferred it over the equals sign, he forgot to change it to a divide sign.
    Distributive error, did not distribute the - to the z

    ReplyDelete
  17. Student P has put way too many spaces. the Majority of the mistakes made by students is due to wrong conversions. They forgot about the - and + sometimes leading it to be confusing.

    ReplyDelete
  18. Student G - Arithmetic error and did not bracket the numerator, confusion if [2z-(zp/p)] OR [(2z-zp)/p]

    ReplyDelete
  19. Student D:
    Did not divide the p

    ReplyDelete
  20. Student N
    It is supposed to be 2Z as the numerator of the fraction where P is the denominator and not the other way around with Z being the numerator.

    ReplyDelete